Do the following:
Because the parameter is an unsigned short integer, it is an integer of 16 bits. therefore
16 binary: 00000000010000.
Move four places to the right: 000000000001.
That is decimal 1.
Divide by 256 to find the remainder, which is 1 of course.
Similarly,
256 binary: 0000000 1, 00000000.
Move four positions to the right:
00000000,000 10000
That is decimal 16.
Divide by 256 to find the remainder, which is of course 16.
What, is that enough?