Then △OP 1H 1, △A 1P2H2 and △A2P3H3 are isosceles right triangles.
Let oh1= p1h1= a, then a2=4,
The solution is that a=2 (minus negative value), that is, the abscissa of P 1 is 2.
Let A 1H2=P2H2=b, then (4+b)b=4,
The solution is b=2(- 1+2) (minus the negative value), that is, the abscissa of P2 is 4+b=2( 1+2).
Let A2H3=P3H3=c, then (2a+2b+c)c=4, that is, (42+c)c=4.
The solution is c=2(-2+3) (minus the negative value).
That is, the abscissa of P3 is 2a+2b+c=2(2+3),
... the abscissa of …P20 10/0 is 2 (praise and trample). What's your comment on this answer? Put away comments//high quality or satisfaction or special types or recommended answers dottimewindow.iperformance & window.iperformance.mark ('c _ best',+newdate); Lawyer recommendation service: If your problem has not been solved, please describe your problem in detail and provide free professional consultation through Baidu Law Professional Edition. Other similar problems 2022- 10-3 1 As shown in the figure, it is known that △ op1a12a2 △ a2p3a3 is an isosceles right triangle. 20 12-02- 12 as shown in the figure, it can be known that △OP 1A 1 △ a/2a2 △ a2p3a3 ... are isosceles right-angled triangles with right vertices, located at P3 P2 ... when the right-angled vertices of the triangle ... Guangzhou), as shown in the figure, point A (-1, 0) and point B (1, 2) are known, and point P is determined on the coordinate axis, so that △ABP is a right triangle, satisfying 1620 14-065438+. It is known that △OP 1A 1, △A 1P2A2, △A2P3A3, ... are isosceles right triangles, and the right-angled vertices P 1, P2, P3, ... are all in the function (x52013. PA⊥PB.( 1) as shown in figure (1), when point p is in the first quadrant, find ∠ opa320111. It is known that the straight line l passes through the point P (5. Point P is the moving point, PA ⊥ Pb. 1 Recommended to you: F.context('cmsRight') is especially recommended. [{ ' URL ':'/d 0 1373 f 082025 AAF 5 1 1aa 256 e 9 edab 64034 f 1a 07？ x-BCE-process = image % 2f resize % 2Cm _ lfit % 2Cw _ 450% 2Ch _ 600% 2c limit _ 1% 2f quality % 2Cq _ 85% 2f format % 2Cf _ auto '， ' contractId':'A24KA00562 '，}，{ ' URL ':/builder/bjh-activity/articlesTask？ taskId = 1598082 & aside = 0 & footer = true & from = 0 '，' src ':'/203 FB 80 e 7 bec 54 e 773 ea 0680 ab 389 b 504 fc 26 a2d？ x-BCE-process = image % 2f resize % 2Cm _ lfit % 2Cw _ 450% 2Ch _ 600% 2c limit _ 1% 2f quality % 2Cq _ 85% 2f format % 2Cf _ auto '，' contractId ':' '，}，{ ' URL ':/s？ word = % E6 % AC % A7 % E6 % B4 % B2 % E6 % 9D % AF & sa = searchpromo _ ozb _ zhidao _ tuijian '，' src ':'/3 BF 33 a 87 e 950352 AAF 5 df 4954 143 fbf2b 2 1 18 b6b？ x-BCE-process = image % 2f resize % 2Cm _ lfit % 2Cw _ 450% 2Ch _ 600% 2c limit _ 1% 2f quality % 2Cq _ 85% 2f format % 2Cf _ auto '，' contractId ':' '，}])； Why is the cost of cancer treatment getting higher and higher? The price of electric cars has dropped many times. Is the quality guaranteed? What impact will the "network toilet" have? Is Huaqiang North's second-hand mobile phone reliable? I recommend f.context ('recbrand', [{"img": "\/86D6277F9E2F07083523F69DFB 24B 899A901F20d? x-BCE-process = image % 2f resize % 2Cm _ lfit % 2Cw _ 450% 2Ch _ 600% 2c limit _ 1% 2f quality % 2Cq _ 85% 2f format % 2Cf _ auto "，" url":"/hm.js？ 6859 ce 5a af 00 FB 00387 e 6434 E4 FCC 925 "； var s = document . getelementsbytagname(" script ")[0]； s.parentNode.insertBefore(hm，s)； })(); window . TT = 1720943895；