The following procedures verify the referenced results;

# Contains? " stdio.h "

int？ Master ()

{

int？ a[2][3]={ 1，2，3，4，5，6}，(*p)[3]，I；

p = a；

printf(" *(p+2)= % u \ n " ,*(p+2))；

printf("p[2]=%u\n "，p[2])；

printf(" p[ 1]+ 1 = % u \ n "，p[ 1]+ 1)；

printf("(p+ 1)+2=%u\n "，(p+ 1)+2)；

Printf ("address? Are you online? p:\ n ")；

For what? (I = 0； I<3; i++)？ printf("p[%d]=%u，value=%d\n "，I，p[i]，* p[I])；

Printf ("address? Yes? a=%u\n "，a)；

System ("suspended");

Return? (0);

}p[0] is the first address of array A, pointing to the first row of the array. The array has three elements, and each integer occupies 2 bytes (address);

P[ 1] is the first address in the second row of array A, and it also has three elements. 65480-65474=6, which is the storage address of three integers.

Array A has six elements and only two rows. P[2] is already the first address after array A and does not belong to array A. ..

*(p+2)=p[2], which is the first address after array A and does not belong to array A. ×

P[2] is the first address after array A and does not belong to array A..×

P[ 1]+ 1 is the address of the second element in the second row of array A, which is a correct reference. √

(p+ 1)+2, which means p+3, even in A ×