The process is as follows:
# include & ltiostream.h & gt
# Define n 2
# Define m 2
# Define l 2
void main()
{
int shuz[n][m][l]，I，j，k；
int max，min，maxx，maxy，maxz，minx，miny，minz
Cout & lt& lt Please enter a three-dimensional array which is
for(I = 0； I & ltn；; I++)// Enter a three-dimensional array.
for(j = 0； j & ltm； j++)
for(k = 0； k & ltl； k++)
CIN & gt； & gtshuz[I][j][k]；
for(I = 0； I & ltn；; I++)// Output a three-dimensional array.
{
for(j = 0； j & ltm； j++)
{
for(k = 0； k & ltl； k++)
cout & lt& ltshuz[I][j][k]& lt； & lt" ";
cout & lt& lt" ";
}
cout & lt& ltendl
}
cout & lt& ltendl
max = shuz[0][0][0]；
maxx = 0；
maxy = 0；
maxz = 0；
for(I = 0； I & ltn；; I++)// Find the maximum value and its subscript.
for(j = 0； j & ltm； j++)
for(k = 0； k & ltl； k++)
if(shuz[I][j][k]& gt； Max)// If there is something bigger than it, assign it accordingly.
{
maxx = I；
maxy = j；
maxz = k；
max = shuz[I][j][k]；
}
Cout & lt& lt "Maximum quantity is"
Cout & lt& lt its subscript is: "<&l tmaxx & lt<" "<< maxy & lt" "<< maxz & lt< endl.
minx = 0；
miny = 0；
minz = 0；
min = shuz[0][0][0]；
for(I = 0； I & ltn；; I++)// Find the minimum value and its subscript.
for(j = 0； j & ltm； j++)
for(k = 0； k & ltl； k++)
if(shuz[I][j][k]& lt； Min)// If there is something smaller than it, assign it accordingly.
{
minx = I；
miny = j；
minz = k；
min = shuz[I][j][k]；
}
Cout & lt& lt "Minimum quantity is"
Cout & lt& lt its subscript is: "<< crazy girl & lt<" "<< miny & lt" "<< minz & lt< endl.
}
You can ask me again if you don't understand! ! ! !