The melting point of aluminum is: 660℃

The room temperature is set at 0℃

One ton of aluminum = 1000 kg

0.88× 1000×(660-0)= 580800 kj

Therefore, the heat required to raise the temperature from 0 to the melting point is 580800KJ.

The latent heat of melting of pure aluminum is 393KJ/Kg.

Therefore, the latent heat of melting of 1T aluminum is * * *: 1000*393KJ=393000KJ.

Therefore, the heat consumption of 1T aluminum smelting is: 580800+393000=973800KJ.