The lower 52 digits are the base number, and all of them are filled in here as 1.
1 1 bit is the index, and the 1 1 bit index can represent-1024~ 1023, which specifies that all bits are added with 1023, so the index here is filled with 2046 bits.
Most significant bit is a symbol, and 0 means+.
The test code is as follows:
# Contains? & ltstdio.h & gt？ //For? Print function
# Contains? & ltstring.h & gt// For? memcpy
# Definition? MAX_BASE？ (0xfffffffffffffLL)？ //52? Bit? basis
# Definition? MAX_POW？ (2046LL？ & lt& lt？ 52) // 12? Bit? Pow (base? *? 2^pow)
# Definition? SIGN_BIT？ (0x 1LL？ & lt& lt？ 63)
Invalid? PrintBits (long? Dragon? ll)
{
Dragon? Dragon? Mask? =? 1;
for(int？ i=sizeof(long？ Dragon) *? 8? -? 1; ? I & gt=0; ? I-)
{
printf("% 1d "，(ll？ & amp？ Mask? & lt& lt？ Me)? 1:? 0);
}
printf(" \ n ")；
}
int？ Master ()
{
Dragon? Dragon? ll？ =? 0;
ll？ |=? MAX _ POW
ll？ |=? MAX _ BASE
print bits(ll)；
Double? d；
memcpy(& amp； d，？ & ampll，？ sizeof(ll))；
printf("Max？ Double? Is:? %e\n "，d)；
ll？ |=? SIGN _ BIT
memcpy(& amp； d，？ & ampll，？ sizeof(ll))；
printf("Min？ Double? Is:? %e\n "，d)；
Return? 0;
}