int a = bytes[0]& lt； & lt24+ bytes [1] < & lt 16+ bytes [2] < & lt8+ bytes [3];

+and

So the above formula becomes bytes [0] < <; 46 & lt& lt38 & lt& lt30

Obviously, after so many left shifts,

A must be equal to 0.

Just put brackets around each item in the formula.

int a =(bytes[0]& lt； & lt24)+(bytes[ 1]& lt； & lt 16)+(bytes[2]& lt； & lt8)+ bytes [3];

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Numbers are stored in the computer in binary form.

For example, 22 is 000 10 1 10.