(2014?Taiyuan No. 2 Model) A small circular ceramic piece is kept parallel to the ground and released from a high place. The small ceramic piece directly hits the ground without being broken.

(1) The acceleration of the falling tile is mg-kmg=ma1

a1=g-kg=10-0.1×10m/s2=9m/s2

< p>The speed when landing is 2a1h=v2

v=2a1h=2×9×0.18m/s=1.8m/s

(2) The ceramic piece and the cylinder together The acceleration of falling is a2=a1

The speed of the tile when the cylinder falls is 2a2H=v12

v1=2a2h=2×9×4.5m/s=9m/s< /p>

The acceleration of the continued falling of the ceramic piece is mg-kmg-μmg=ma3

a3=-36m/s2

v2-v21=2a3L

< p>Plug in the data and get L=1.08m

Answer: (1) When the tile hits the ground directly instead of being broken, the maximum speed v of the tile hitting the ground is 1.8m/s;

(2) The length L of the cylinder is 1.08m.