Because there are only three situations, three judgments are enough;
The code is as follows:
Floating x;
float y = 0.0
int k；
Printf ("Please enter a
Because there are only three situations, three judgments are enough;
The code is as follows:
Floating x;
float y = 0.0
int k；
Printf ("Please enter a floating point number! \ n ")；
scanf("%f "，& ampx)；
if(x & lt； 1)k = 0；
else if(x & gt； = 1。 & ampx & lt 10)k = 1；
else if(x & gt； 10)k = 2；
Switch (k)
{
Case 0: y = x; Break;
Case1:y = 2 * x-1; Break;
Case 2: y = 3 * x-11; Break;
}
printf("y=%f "，y)；