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10 elements in the output array.
# include & ltstdio.h & gt

void main()

{

int a[ 10]; //Define an array A with 10 integer data.

int I; //define the integer variable i.

for(I = 0; I< 10; I++) // The loop starts with i=0. Every time the loop body is executed, I will add 1, as long as I.

scanf("%d ",& ampa[I]); //For the loop body, initialize the array A, enter the number 10, and assign them to a[0], a[ 1] ... a [9] in turn.

printf(" \ n "); //output a newline character, that is, a newline character. ...

for(I = 0; I< 10; I++)// The loop starts with i=0. Every time the loop body is executed, I will add 1, as long as I.

printf ("%d ",a[I]); //loop body, input array a, output [0], a[ 1] ... an array element of [9] 10 is arranged in sequence.

printf(" \ n "); //Output a newline, that is, a newline ... "\n" is a newline.

}//End of program

The previous for is to assign a value to the array a.

The latter is used to output the values of elements in array a.

Brother just started to learn, study hard, C language is still more useful.