Each type should be determined according to the compiler. The following is the result of the 32-bit machine standard

char str[ ]= ”Hello”;

char * p=str;

int n=10;

sizeof(str)=( 6 )

sizeofchar str[ ]= ”Hello”;/*yes Wrong, it should be repeated */

char *p=str;

int n=10;

sizeof(str)=( 6 )/ *To find the total number of bytes, not the length, compare the strlen function*/

sizeof(p)=(4)/*On a 32 machine*/

sizeof(n)=( 4 )

void func(char str[100])

{ }

sizeof(str)=( 4 )/* When an array is passed to a function as a parameter, a pointer is passed instead of an array. What is passed is the first address of the array. Haha~~, keep this in mind*/

(p)=(str)

sizeof(n)=( 4 )

void func(char str[100])

{ }

sizeof(str)=( 4 )

It feels weird, they are all the same, maybe I have lost the process of change...