(20 13? As shown in the figure, there is a smooth crown block at the D end of the bracket ABCD with an inclination of 37, and the size and mass can be ignored, and there is one at the A point.

The object moves in a straight line at a uniform speed along BD, and the resultant force is zero, which is obtained according to the equilibrium condition.

F=f+mgsin37

N=mgcos37

F=μN

Meanwhile, f = micron gcos 37+mgsin 37.

For the bracket: when the bracket is about to rotate around point A, the object slides up the longest distance. Because the resultant force of the ropes on both sides of the pulley passes through point A, the arm of force relative to point A is equal to zero, and the moment is zero.

The stress analysis of the bracket is shown in the figure, which is obtained from the moment balance condition.

f？ ABsin37 =N？ (ABcos37 -s)

Where DC=0.3m, AB=0.4m, s=0.248m, substituted into the solution.

If f increases, it can be seen from the above formula that s has nothing to do with the size of f, so the maximum distance for an object to slide upward remains unchanged, then s' = s.

So the answer is: 0.248, equal to

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