# Contains? & ltstring.h & gt
typedef？ Not signed? Charles? uchar
typedef？ Not signed? intuint
//conversion function
//Temp？ Character array
//pout? Int array
//Length? Character array length
//Assume that the character array contains an even number of elements.
//If it is odd, the following processing needs to be added:
//Check whether the length is odd, and if it is, dynamically allocate an array of length+1 char.
//Clear all data and copy the contents of Temp to the dynamically allocated array.
//According to the following case that the length is even.
//Release dynamically allocated memory
//According to the requirements of the problem, the int type should be stored in a small terminal.
//If you are smart, you can write a function to check the byte order.
Invalid? Exchange (const? Ucal? * Temperature? uint？ * pout,? Ucal? Length)
{
int？ Me? =? 0;
For what? (; ? Me? & lt？ Length? /? 2; ? i++)
{
//small end, copy it directly in the original order.
//If it is a big end, you can change the byte order.
Memcpy (pout, temperature? 2);
pout++； //int pointer moves back one bit.
temp+= 2； //The character byte is shifted back two places.
}
}
//Test code
int？ Major (invalid)
{
int？ Me;
uint？ Array [20]? =? {0};
Ucal? Start []? =? {0x80，0xF 1，0x58，0x03，0xC 1，0xEA，0x8F，0x 06 }；
Exchange (start,? Array? sizeof(Start))；
For what? (me? =? 0; ? Me? & lt？ 20; ? i++)
{
What if? (array[i]？ ! =? 0)
{
printf("0x%04X？" ,? array[I])；
}
}
printf(" \ n ")；
Return? 0;
} output screenshot: