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(1) According to the right-hand rule, the direction of induced current is adcb, as shown in the figure:

(2)n = 3000 rpm? The speed of the coil rotates at a uniform speed, so the angular velocity of the coil ω = ω =100 π rad/s/s.

The maximum value of induced electromotive force is: Em=nBSω=3 14V.

Therefore, the expression of the instantaneous value of the induced electromotive force is e = nb ω SCOS ω t = 314cos100 π t (v).

(3) The effective value of electromotive force is E=Em2.

Current I=ER+r

The work done by the external force is equal to the electric work, that is, W = I2 (R+R) t = 98.6J..

(4) When the coil rotates 90 from the position shown in the figure, within 90 △φ = BSS?

What is the electricity passing through R? q = N△φR+R = 0. 1C

Answer: (1) as shown in the figure.

(2) The instantaneous expression of the induced electromotive force of the coil e = 3 14cos 100π t (v).

(3) When the coil rotates once, the external force is 98.6J.

(4) Does the resistor R flow when it rotates 90 from the position shown in the figure? The power of is 0.1c.