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How many bytes does an integer take up?
Question 1: How many bytes are integers? It's 4 bytes. Integer types are divided into signed integer and unsigned integer, and one byte is 8 bits. That is, a signed integer can represent the integer size with 7 bits, that is,-128 to 127, even if it is unsigned, that is, 0 to 255. How can such a small range represent such a large amount of data now? Yes, it is 4 bytes, and 4 bytes is 32 bits, which is the bus width of the current general system, that is, the memory address retrieval range, so the integer range that an int type can represent now is -(3 1 to the second power of 3 1-1.

Question 2: How many bytes does a number need?

An English letter, number-7/8 bytes, is seven binary bits, and the eighth letter has other uses, such as parity, so it can be counted as a byte. (8 bits)

One Chinese character-two bytes.

Integers depend on the type and are usually very long. For example, the integer of 16 bit machine is 16 bit, with two bytes. A 32-bit machine is 4 bytes. And int64

An integer of type.

As for the real numbers in C, there are 32 bits (floating point) and 64 bits (double precision). There are 80-bit types in other languages, which are called extended precision real numbers. Mainly the extended precision real number register inside the cpu, 80 bits. Ensure that the double real number operation does not lose precision.

Question 3: How an integer takes up 4 bytes depends on what type of variable you use to install it.

Int occupies 32 bits, which means 4 bytes. Two bytes shorter.

Question 4: An integer takes up four bytes. Why can a byte store 257 numbers? All the data in the computer are binary, so are the numbers. Specify that every 8 bits is one byte.

The former means that an integer occupies a binary bit width of 4 bytes, that is, 4*8=32 bits.

The latter represents the range of numbers that one byte can represent.

There are 8 bits in a byte,

Where the high bit is the sign bit (indicating that plus or minus 0 is positive and 1 is negative), the number that can be included is

100000 1 to111111(-/kloc

0000000 1 to 011111(1to120).

And 000000000 and 1000000 (+0 and -0 but -0 are generally called-128).

So the range of bytes is-128 to 127.

So127 * 2+2 = 256 (2 8).

The number of bits that can be stored in a byte is 256, not 257.

So the number of numbers that an integer can represent is 256 4.

But most significant bit still represents the sign bit.

Question 5: How many bytes does C language integer data int occupy according to the compiler? Different compilers have different regulations. The ANSI standard defines int as 2 bytes, TC as 2 bytes according to the ANSI standard, and its int as 2 bytes. But in VC, an int is 4 bytes.

Question 6: One character is equal to several bytes. Different characters occupy different bytes.

ASCII code:

An English letter (regardless of case) takes up one byte and a Chinese character takes up two bytes. A sequence of binary numbers, as a numerical unit in a computer, is usually an 8-bit binary number, which is converted into decimal. The minimum value is 0 and the maximum value is 255. For example, ASCII code is one byte.

UTF 8 encoding:

One English character equals one byte, and one Chinese (including traditional Chinese) equals three bytes.

Unicode encoding:

One English is equal to two bytes, and one Chinese (including traditional Chinese) is equal to two bytes.

Symbol:

English punctuation takes up one byte and Chinese punctuation takes up two bytes. For example, the English period "."accounts for 1 byte, and the Chinese period "."has a size of 2 bytes.

Question: How many bytes does int account for in java? This is the number of bytes occupied by the basic type of memory in 8 (the value range is 2 to the power of (number of bytes X8- 1)).

1. integer

Value range of digits required for type storage

Byte 1 byte1* 8 (-2 power of 3 1 to 2 power of 31-1)

Short 2 bytes 2 * 8-32768 ~ 32767

Int 4 byte 4*8 (-2 to the 63rd power 2-1)

8 bytes long, 8 * 8- 128 ~ 127

2. Floating-point type

A note on the number of bits required for type storage

Floating-point 4 bytes, 4*8 floating-point values have a suffix f (for example, 3. 14F).

Double 8 bytes 8*8 Floating-point values without suffix f (such as 3. 14) are double by default.

3. Character type

Number of bits required for type storage

Character 2 Byte 2*8

4. Boolean storage demand digit range

Boolean type 1 byte 1*8 false, true

Question 8: How many bytes does the short integer in 8:c+++occupy? The abbreviation of standard C and C++ is 2 bytes (16 bits, which can represent 32768 to 32767). Char is 1 byte.