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A simple math application problem in grade one.
(1) Suppose that the single-piece clothing of Type A and Type B is X yuan and Y yuan respectively.

Then 9x+10y =1810, 12x+8y= 1880.

Calculated x=90 yuan, y= 100 yuan.

(2) Suppose you buy a B-type garment, then the A-type garment is 2a+4 pieces.

2a+4 ≤ 28 According to the meaning of the question.

(2a+4)× 18+30a≥699

The solution is 9.5≤a≤ 12.

Because a is an integer, if a= 10, 1 1 and 12 are substituted into 2a+4 respectively, we can get 24, 26 and 28.

* * * Three purchase plans. First, there are 24 pieces of A-type clothes and 24 pieces of B-type clothes 10.

The second type, type A, 26 sheets, type B 1 1 sheet.

The third type, a type with 28 pieces, b type 12 pieces.