The amount of carbon dioxide produced by r.44g sample and sufficient hydrochloric acid is: 0.684L44.4L/mol = 0.0rmol;

The amount of carbon dioxide produced by the decomposition of r.44g sample is 0.114L44.4l/mol = 0.00 tamol,

4NaH or Delta. ? Na4 Seven or +H4O+ Seven O4 =

4mol？ 1mol？ 1 mol

0.0 1 mol 0.00 talmol 0.00 talmol

The amount of nahheptanol in the sample is 0.0 1mol, and the amount of sodium carbonate in the sample is 0.0mol-0.0 1mol = 0.04mol.

The mass of H4O in the sample is: 0.68g-0.00tamol×18g/mol-0.00tamol× 44g/mol = 0.r6g;

The amount of H4O in the sample is 0.r6g 18g/mol=0.04mol,

∴f: person: z = 0.04mol: 0.01.04mol = 4:1.4.

So choose seven.