Current location - Plastic Surgery and Aesthetics Network - Wedding supplies - (20 13? Ganzhou simulation) as shown in the figure, the straight line l 1∨L2∨L3∨l4∨l5 is known, and the distance between two adjacent parallel lines is 6 cm; Now put a rectangular New Year card.
(20 13? Ganzhou simulation) as shown in the figure, the straight line l 1∨L2∨L3∨l4∨l5 is known, and the distance between two adjacent parallel lines is 6 cm; Now put a rectangular New Year card.
Solution: (1) Solution 1: DH⊥l 1 with intersection D as point M, intersection l2 as point H, and intersection B as BG⊥l 1

∫l 1∑L2,

∴∠DHE=90,

∴∠DHE=∠BAE=90,

∫ The quadrilateral BFDE happens to be a diamond,

∴BE=DE,

In △DEH and △ BEI, ∠ DHE = ∠ BEI = 90 ∠ DEH = ∠ BEI = DE,

∴△DEH≌△BEA(AAS),

∴AB=DH,

∫DH = 2×6 = 12cm,

∴AB= 12cm,

BG = 6cm,

∴∠bak=30;

Solution 2:∫ straight line l 1∪L2∪L3∪l4∪l5, and the distance between two adjacent parallel lines is 6cm.

According to the bisection theorem of parallel lines, DE=2AE,

In addition, the quadrilateral BFDE happens to be a diamond,

∴BE=DE=2AE,

And BAE = 90,

∴∠ABE=30,

∫l 1∑L2,

∴∠bak=∠abe=30;

(2)BAK = 30 degrees, BAE=90 degrees,

∴∠DAM=90 -30 =60,

∵BG=6cm,DM= 18cm,

∴AB=6sin30 = 12cm,

AD= 12sin60 = 123cm,

The area of rectangular ABCD is12×123 =1443cm2.