Current location - Plastic Surgery and Aesthetics Network - Wedding planning company - (20 13? Deductive inquiry-air resistance research: (1) When an object moves up and down in the air, it will be resisted by the air.
(20 13? Deductive inquiry-air resistance research: (1) When an object moves up and down in the air, it will be resisted by the air.
(1) As can be seen from Figure A, F is a quadratic function about R, so F is directly proportional to the square of R, and it is also known that F is directly proportional to velocity V, so the relationship between resistance F and velocity V and radius R can be expressed as f = kvr2.

(2) According to (1), when the hydrogen balloon with radius r moves at speed v, the resistance f is directly proportional to the speed v, so if the volume of the hydrogen balloon remains the same during its ascent, the greater the speed, the greater the resistance.

(3) When the hydrogen balloon rises in the air, it is affected by gravity, buoyancy and resistance.

Gravity on the hydrogen balloon: g = mg = ρ VG = 43 π R3 ρ 0g;

Buoyancy of hydrogen balloon: f float = ρ VG = 43 π R3 ρ g;

According to (1), when the speed of the hydrogen balloon is vT, the resistance of the hydrogen balloon is f=kvTr2.

According to Figure B, when the speed is vT, the hydrogen balloon will rise at a uniform speed, and the resultant force on the hydrogen balloon is zero, so G+f=F floats.

43πr3ρ0g+kvTr2=43πr3ρg

The solution is vt = 4 π r (p? ρ0)g3k

So the answer is: (1); (2) large; (3)4πr(ρ? ρ0)g3k。