One day, Li Shifu produced a batch of parts, which were divided into two piles, A and B. If 15 parts were taken from pile A and put into pile B, the number of parts in the two piles would be equal. If 15 parts are taken from pile B and put into pile A, the number of parts in pile A is three times that of pile B, then how many original parts are there in pile A? How many original parts are there in stack B? How many parts did Li Shifu produce this day?

Solution: If there are X parts in stack B at this time, there are (3x-30) in stack A, and the equation can be obtained according to the meaning of the question.

3x-30-x= 15+ 15，

The solution is x=30,

So there are 3×30-30=60 piles of armor at this time.

Then the original heap B is: 30+ 15=45 (pieces),

Stack A originally had parts: 60+ 15=75 (pieces),

Parts processed in Li Shifu on this day: 45+75= 120 (pieces),

A: In the past, there were 75 parts in Stack A, but today Li Shifu has produced 120 parts.

So the answer is: 75 120.