Current location - Plastic Surgery and Aesthetics Network - Wedding planning company - (20 14? As shown in the figure, a horizontal plane is tangent to the 14 vertical arc trajectory BC with a radius of R=0.5m, and stands at point B with a mass of m=l kg.
(20 14? As shown in the figure, a horizontal plane is tangent to the 14 vertical arc trajectory BC with a radius of R=0.5m, and stands at point B with a mass of m=l kg.
(1) The object from A to B is obtained by the kinetic energy theorem.

flcosθ-μ(mg+fsinθ)L = 12mv2B

From Newton's second law at point B.

f? n? mg=mv2BR?

Simultaneous solution FN=35.6N n n.

According to Newton's third law, the pressure on a circular orbit is 35.6 N;

(2) In the process from B to C, it is obtained by kinetic energy theorem.

-mgR-Wf=0- 12mv2B

Substitute the data to get WF =1.4j;

Answer: (1) When the object reaches point B, the pressure on the circular arc orbit is 35.6 N. 。

(2) The work done by an object to overcome the frictional resistance on the arc trajectory BC is1.4j. 。