So let's look at the difference between the two kinds of deformation.

The first thing to say is the priority of operators. The [] operator takes precedence over the * operator. So if you want to convert int p[2][4] into pointers, you need to use () to increase the priority of *: int (*p)[4]. This means that p is a pointer, and the element it points to is an array containing four plastic elements. Therefore, it is a two-dimensional array of n*4.

Int *p[4] means that p is an array, and an integer pointer is stored in the array. 4* 1 one-dimensional array.