{

int x，n，s=0，y，z；

scanf("%d%d "，& ampn & amp； y)； //Enter an integer and integer digits.

for(z = 1； z & lt= y； z++)

{

x = n % 10；

n = n/ 10；

s+= x * x；

}

printf(" %d "，s)；

}

This program requires you to enter digits. Of course, the number of digits can also be calculated by the number entered. Think for yourself. The same scenery on the second floor, you can't just think about the results, if you can't find the number.

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