Int a[3][2]={0}, declare an integer array and append the initial value of 0 to the array (all positions are appended with 0).

(*ptr)[2], declare a pointer to an array, named ptr.

for(I = 0； I<2; i++){ ptr = a+I； scanf("%d "，ptr)； ptr++； } Enter an integer value in the array. If you enter 1, 2, 3, the storage format is

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Sufficient pt r++on the surface; I don't think it's useful. Because at the beginning of each cycle, ptr is newly added. ++has no effect either. At the beginning of each cycle, ptr points to the first address of the I+ 1 line.

for(I = 0； I<3; i++)

{ for(j = 0； j & lt2; j++) printf("%2d "，a[I][j])；

printf(" \ n ")；

Outputs the elements in the array, each occupying two positions.

I think you entered 123 with no spaces in the middle, so the system recognizes it as 123 and counts it as a number. You can try adding spaces. For example: 1 2 3 Enter. The output should be

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