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Can Longyan Fingers be Remodeled?
The pencil is stationary, and the pressure of two fingers is a pair of balancing forces.

The pressure of two fingers on the pencil is equal,

The finger pressure on the pencil and the pencil opponent pressure are a pair of interaction forces.

∴ These two forces are equal, that is, the pencil pressure on two fingers is the same, that is, f1= F2;

As can be seen from the figure, the stress area of the right finger is relatively small, and according to p=FS, the stress on the right finger is relatively large, that is, p1< p2;

So choose C.