The inner angle of this hexagon is 120,

The regular hexagon ABCDEF rotates 60 clockwise around vertex a, and then coincides with the regular hexagon AGHMNP.

Point b can only coincide with point g,

Connect AE, make a vertical line to AE through point F, and the vertical foot is I,

∵EF=AF= 1,IF⊥AE，

∴AE=2EI，

∫∠AFE = 120，

∴∠EFI=60，

∴EI=EF？ sin60 = 1×32=32，

∴AE=2×32=3，

∴ The route that E passes through is an arc with A as the center, AE as the radius and the central angle of 60 degrees.

∴E In the whole rotation process, the path length is 60×π× 3 180 = 33 π.

So the answer is: g, 33 π.