The inner angle of this hexagon is 120,
The regular hexagon ABCDEF rotates 60 clockwise around vertex a, and then coincides with the regular hexagon AGHMNP.
Point b can only coincide with point g,
Connect AE, make a vertical line to AE through point F, and the vertical foot is I,
∵EF=AF= 1,IF⊥AE,
∴AE=2EI,
∫∠AFE = 120,
∴∠EFI=60,
∴EI=EF? sin60 = 1×32=32,
∴AE=2×32=3,
∴ The route that E passes through is an arc with A as the center, AE as the radius and the central angle of 60 degrees.
∴E In the whole rotation process, the path length is 60×π× 3 180 = 33 π.
So the answer is: g, 33 π.