According to the meaning of the question, 1 card is right because of finger friction, and c is wrong; If there is relative sliding between the second card and the 53rd card, the friction force F of one card to the card above it must be greater than that of the card below it. Under F, the coefficient of friction between cards is μ2, so the gravity of each card is mg. If F is above =μ2FN, then F is below =μ2(mg+FN), and always F is below > F, that is to say, there can be no relative sliding between the second card and the 53rd card. If the second card and the 53rd card are regarded as a whole, the whole will turn right due to the friction of 1 card, and Newton's third law tells us that the friction of the 53rd card and the 54th card will turn right, so the friction of the desktop against the 54th card will turn left.