Solution: As shown in the figure, the intersection point D is DE⊥AB, and the vertical foot E. 。

In Rt△ADE, DE=BC= 10m, ∠ ade = 33,

tan∠ADE=AEDE，

∴AE=DE？ tan∠ADE≈ 10×0.65=6.5(m)。 ? (5 points)

∴ab=ae+be=ae+cd=6.5+ 1.5=8(m).

Answer: The height AB of the tree is about 8m. (7 points)