Hehe, hello, landlord. Well, I generally like to deal with problems in simple but useful ways. After reading the answers upstairs, I felt good, but it was too complicated. . . Hehe, we can actually have the idea of taking out the numbers 1, 2, 3 and 4 on each digit of 1234 and storing them in the array respectively. The specific procedures are as follows:

# include & ltstdio.h & gt

Master ()

{

int a，I；

char b[ 100]；

scanf("%d "，& ampa)；

for(I = 0； a & gt0; a=a/ 10)

b[i++]= a % 10+48；

b[I]= 0；

for(I = I- 1； I & gt=0; I-)

printf ("%c\n "，b[I])；

}

What needs to be explained here is that the ASCII code of the number 0 is 48, and so on, so if you want to save the array correctly, you must add 48, followed by b [I] = 0;

Because all arrays must have the ending character' \ 0' (ASCII code is 0) to output normally.