E=Blv
where L E=Bdvsinθ, so E = bdd.
(2) The heating power on the resistor R is the electric power of the resistor R, so
PR = I2r = B2D2V2RSIN2θ
(3) When the conductor moves at a constant speed V, the conductor rod is subjected to a pulling force F and an ampere force F, and the two forces are balanced, that is,
f = f? Ann = bil = b2l2vr
p = Fv = b2l2v2r?
P = b2d2v2rsin2θ
It can also be analyzed from the relationship of energy conversion and conservation. Because the conductor moves at a uniform speed, all the mechanical work done by the tensile force is converted into electric energy and joule heat, so
p machine = p heat = b2d2v2rsin2θ?
a: (1) the current intensity through the resistor is bdvrsin θ;
(2) the heating power on the resistor r is B2d2v2Rsin2θ;;
(3) The mechanical power of tensile force is B2d2v2Rsin2θ..