Three resistance wires, six terminals, angular connection, the resistance between each two phases is 33 ohms, the voltage is 380 volts, and the algorithm for calculating current and power is obtained.

This is a resistive symmetric load, and the algorithm is very simple:

The total power is equal to the sum of the powers of the three resistors.

Single power: P=UU/R=380*380/33=4375.76 watts ... (33 ohms should be thermal resistance)

Total power: 4375.76 * 3 =13127.28 watts.

The line current of three-phase alternating current under resistive symmetrical load is three times that of a single resistive current;

I=(U/R)* radical number 3 = (380/33) *1.732 =19.94a.

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