It should be1548+4 * 2 * 5+4 * 2 (1548+the size of two int[5] arrays+the size of two int).
If it is not, it is not certain that it can be calculated by a[0][0], but the address of A should be determined.
I can't solve it because the pointer 1584 is not sure whether it is stored in the source address or a copied pointer according to the conditions you gave, so I can't do it&; (1548) get the address of a.
The algorithm for using addresses is as follows:
Suppose the address of a is int * * ptr _ a;;
Then & (a [2] [2]) = * (ptr _ a+2)+2;
For int type integer shift a >;; & gtB, the system first uses B as the remainder of 32, and the result is a truly shifted number.
For integer shift of type long, the same as above,