{
printf("%f ",change(9,8));
返回;}
double change(int x,int y)
double f_num,result
int i,n = 1;
f _ num =(double)y;while(n/= 1)++ n;
for(I = ;我& ltn;++ I)
f _ num/= 1;
结果=(double)x+f _ num;
返回return
}