The area of the rhombus Let the area of the rhombus be S, the side length be A, the height be B, the two diagonal lines be C and D respectively, and the minimum internal angle be ∠ θ, then there are:
1, S=ab (the area of rhombic parallelogram is equal to the base multiplied by the height);
2.S=cd÷2 (the area of a quadrangle with rhombus and other diagonals perpendicular to each other is equal to half of the product of two diagonals);
3. s = a 2 symplectic θ.
The formula of diamond circumference is:
C=4a (where c is the perimeter and a is the side length of the diamond).
On the same plane, a group of parallelograms with equal adjacent sides are rhombic, and quadrilaterals with equal four sides are rhombic.
Further reading: the essence of diamonds
1, the diamond has all the properties of a parallelogram;
2. All four sides of the diamond are equal;
3. The diagonals of the rhombus are equally divided vertically with each other and equally with each group of diagonals;
4. The diamond is an axisymmetric figure with two symmetrical axes, that is, the straight lines where the two diagonals are located;
5. A diamond is a figure with a symmetrical center.