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Why does vb 1 decompose under alkaline conditions?
The reason why vb 1 decomposes under alkaline conditions: methanol attacks this carbocation, and the carbonyl ring dissociates under acidic conditions. Firstly, H+ ions attack the oxygen atom of epoxy, and at the same time, alcohol is obtained, and a carbocation with the most branches is obtained, and the obtained methyl ether is 2- methoxy alcohol connecting the carbon atoms with the most substituents.

White crystal, soluble in water, slightly soluble in ethanol and chloroform; Hydrochloride is a white crystalline powder, which is easily deliquescent and bitter in taste. It is soluble in water, slightly soluble in ethanol and insoluble in ether, and its melting point is 245 ~ 250℃. It is easy to decompose and deteriorate under alkaline conditions. It can be prepared by a synthetic route using acrylonitrile or malononitrile as raw materials. Usually, β-ethyl propionate, ethyl formate and sodium metal wire are used as raw materials for synthesis and production.

generally speaking

The alkalinity of a substance depends on its ability to accept protons and the stability of the atomic groups formed. For example, NH3 can accept BF3 to form BF3+NH3-, but the stability of this ion is poor, so NH3 is weakly alkaline. NH2- forms stable NH3 when it accepts H+, so NH2- is strongly alkaline. In aqueous solution, NaOH has the same alkalinity as KOH, so it is called leveling solvent, but in some solvents, it can show different alkalinity differences, so it is called distinguishing solvent.