Step 1, the r-θ coordinates of two currents on the complex plane are converted into x-y coordinates: real part = amplitude × cos (amplitude angle); Imaginary part = amplitude × sin (amplitude angle) I1= 4+6.9282ji2 = 5.1962? 3j, step two,

Add:

The real part and the real part are added, and the imaginary part and the imaginary part are added. I = 9. 1962+3.9282j Step 3, the total current is switched back from the x-y coordinate to the r-θ coordinate:

Amplitude = √ (real part? +imaginary part? ); Phase = arc tangent (imaginary/real) amplitude = 10 amplitude angle = 23. 13? Therefore, the current i = 10sin(ωt+23. 13? A it's very simple.