Solution: (1) Proof: Connect OE, BE,
∵AB is the diameter.
∴BE⊥AC.
∵D is the midpoint of BC,
∴DC=DB.
∴∠DBE=∠DEB.
And OE=OB,
∴∠OBE=∠OEB.
∴∠DBE+∠OBE=∠DEB+∠OEB.
That is, ∠ABD=∠OED.
But ∠ABC=90°,
∴∠OED=90°.
∴DE is the tangent of ⊙O.
(2) Method 1: ∵∠ABC=90°, AB=23, BC=2DE=6,
∴AC=43.
∴BE=3.
∴AE=3;
Method 2: ∵AC=AB2+BC2=(23)2+62=43 (8 points)
∴BE =AB?BCAC=2 Liked and Disliked What is your evaluation of this answer? Comments are closed // High quality or satisfactory or special type or recommended answer. Time window.iPerformance && window.iPerformance.mark('c_best', +new Date); Recommended lawyer service: If your problem is not solved, please provide details Describe your problem and get free professional consultation through Baidu Lulin. Other similar problems 2012-01-03 As shown in the figure, △ABC is a right triangle, ∠ABC=90°, and ⊙O with AB as the diameter intersects AC at point E , point D is the midpoint of side BC, connecting DE. 1552012-12-16 As shown in the figure, △ABC is a right triangle, ∠ABC=90°, ⊙O with AB as the diameter intersects AC at point E, point D is the midpoint of side BC, and connects DE. 212010-10-18 As shown in the figure, in triangle ABC, angle B = 2 angle C, AD is perpendicular to BC and D, and M is the midpoint of BC. Verify: DM=1/2AB492014-02-12As shown in the figure, in triangle ABC, angle ACB=90°, angle B>angle A, point D is the midpoint of side AB, DE is parallel to BC and intersects AC at point E2512012-06 -23 Known: As shown in the figure, in the right triangle ABC, ∠BAC=90°, AB=AC, D is the midpoint of BC 122011-10-26 In the Rt triangle ABC, the angle ABC=90 degrees.
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