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A suit of 96 yuan, in which pants are cheaper than a coat of 2.7 yuan. How much is a pair of trousers?
Solution: Let a coat be X yuan and a pair of trousers be (1-7) X yuan.

X+( 1-2/7) X = 96

X+7x 5x=96

12x=96。

X = 96/7 12

X = 96× 65438+7/02

x=56

Pants price = (1-2)x=7) x = 5/7× 56 = 40 yuan.

A: A pair of pants, 40 yuan.

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